Form 5 · Relationship and Algebra

Variation

Variation describes how one quantity changes with another, directly, inversely, or a mix of both.

What is Variation?

This chapter formalises the everyday idea that things change together. In direct variation one quantity rises as another rises; in inverse variation one rises as another falls; combined variation mixes several relationships.

You learn to form the equation, find the constant, and solve for an unknown.

Content standards (DSKP)

The DSKP KSSM sets these content standards for this chapter:

The key ideas

Direct variation

y ∝ x means y = kx. Double x and y doubles.

Find k from one pair of values, then use it everywhere.

Inverse variation

y ∝ 1/x means y = k/x. As x grows, y shrinks, the shape is a curve, not a line.

Finding the constant k

Every variation problem hinges on finding k first from the given values; everything else follows.

How this chapter is examined

Paper 2 gives a relationship in words (“y varies directly with the square of x”), a pair of values to find k, and then asks you to predict another value. The single most common slip is misreading the type of variation, so the first sentence deserves care.

How to study this chapter

Common mistakes to avoid

  • Confusing direct with inverse variation
  • Forgetting to square or root when the variation involves a power
  • Solving for the answer without finding k first

Joint and combined variation: more than one partner

Beyond simple direct and inverse variation, a quantity can depend on two or more others at the same time. In joint variation, y varies directly with both x and z, written y ∝ xz, so the equation is y = kxz.

In combined variation you mix the two ideas: for example y varies directly with x and inversely with z gives y ∝ x/z, so y = kx/z. The key move is to build the whole relationship into one equation before you do anything else, every quantity it varies directly with goes on top, every quantity it varies inversely with goes on the bottom, and the single constant k multiplies the lot.

You still find k the same way, by substituting one complete set of matching values, and then you can predict a new value by substituting the rest.

Read the type: constant ratio versus constant product

The most common error in this chapter is misreading whether a relationship is direct or inverse, and there are two quick tests that stop it. From the words: in direct variation the two quantities move the same way, as one rises the other rises, while in inverse variation they move in opposite ways, as one rises the other falls.

From a table of values: in direct variation the ratio y ÷ x stays the same for every pair (that constant ratio is k), while in inverse variation the product x × y stays the same for every pair (that constant product is k). So if a table shows the numbers multiply to the same value each time, it is inverse; if they divide to the same value each time, it is direct.

Checking one of these before you write the equation catches the mistake early, while it is still cheap to fix.

When the variable is squared or rooted

Variation often involves a power, and the safe rule is to put the power into the equation from the very start rather than adding it later. If y varies directly with the square of x, the relationship is y = kx², not y = kx; if y varies inversely with the square root of x, it is y = k/√x.

Find k with the power already in place, substitute the given pair, work out x² or √x first, then solve for k, and keep the power there when you predict the next value. The most common slip is to find k as if the relationship were linear and only remember the square at the very end, which throws the constant off.

Reading carefully for phrases like 'the square of', 'the cube of' or 'the square root of' tells you exactly which power to write down.

A worked exam-style example

This example is a combined variation, mixing a direct part and an inverse-square part, exactly the shape a Paper 2 question tends to take.

  1. (a) Directly with x and inversely with z², so y ∝ x/z², which gives y = kx/z².
  2. Substitute the known set x = 12, z = 2, y = 9: 9 = k(12) / 2² = 12k / 4 = 3k.
  3. So 3k = 9, giving k = 3, and the equation is y = 3x/z².
  4. (b) Substitute x = 20 and z = 5: y = 3(20) / 5² = 60 / 25 = 2.4.
  5. (c) Substitute y = 4 and z = 3: 4 = 3x / 3² = 3x / 9 = x / 3.
  6. Multiply both sides by 3: x = 4 × 3 = 12.
  7. Check with part (a): 3(12) / 3² = 36 / 9 = 4, which matches the given y.

Frequently asked questions

How this chapter is examined

SPM Mathematics assesses this chapter across Mathematics Paper 1 (Objective) and Mathematics Paper 2 (Subjective), drawing on the DSKP content standards above. Paper 2 gives marks for working, so showing every step matters.

Common mistakes to avoid

Confusing direct with inverse variation; Forgetting to square or root when the variation involves a power; Solving for the answer without finding k first.

Are any Variation formulae given in the exam?

This chapter has no formula on the exam formula sheet, the working is expected from memory and method.

How do I know if it is direct or inverse variation?

In direct variation both quantities move the same way, one up, the other up, and their ratio y ÷ x stays constant. In inverse variation they move in opposite ways, one up, the other down, and their product x × y stays constant.

Read whether the second quantity rises or falls as the first one rises.

There is a square in the variation, where does it go?

Put the power straight into the equation. If y varies inversely with the square of z, write y = k/z², not y = k/z.

Substitute the given values with the square already in place to find k, then keep the square there when you predict the next value. Adding it only at the end throws k off.

Do I really have to find k first?

Yes, in almost every SPM variation question. The constant k ties the relationship to the specific numbers you are given, and without it you cannot predict a new value.

Find k from the first matching pair, write out the full equation, and only then substitute the second set of values to get the answer.

Source:DSKP KSSM Mathematics Form 4 and 5 (Versi English)· SPM: Format Pentaksiran mulai 2021, Matematik (1449)

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